HackerRank Python Solution - Built-Ins - Zipped!

Zip([iterable, ...]):

• This function returns a list of tuples. The i^th tuple contains the i^th element from each of the argument sequences or iterables.
• If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.

Sample Code:

>>> print zip([1,2,3,4,5,6],'Hacker')
[(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')]
>>> 
>>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1])
[(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)]
>>> 
>>> A = [1,2,3]
>>> B = [6,5,4]
>>> C = [7,8,9]
>>> X = [A] + [B] + [C]
>>> 
>>> print zip(*X)
[(1, 6, 7), (2, 5, 8), (3, 4, 9)]

Task: 

• The National University conducts an examination of N students in X subjects.
• Your task is to compute the average scores of each student.

• The format for the general mark sheet is:

Student ID → ___1_____2_____3_____4_____5__               
Subject 1   |  89    90    78    93    80
Subject 2   |  90    91    85    88    86  
Subject 3   |  91    92    83    89    90.5
            |______________________________
Average        90    91    82    90    85.5 

Input Format:

• The first line contains N and X separated by a space.
• The next X lines contains the space-separated marks obtained by students in a particular subject.

Constraints:

• 0 < N < = 100
• 0 < X <= 100

Output Format:

• Print the averages of all students on separate lines.
• The averages must be correct up to 1 decimal place.

Sample Input:

5 3
89 90 78 93 80
90 91 85 88 86  
91 92 83 89 90.5

Sample Output:

90.0 
91.0 
82.0 
90.0 
85.5      

Explanation:

• Marks obtained by student 1: 89, 90, 91. Average marks of student 1: 270/3 = 90
• Marks obtained by student 2: 90, 91, 92. Average marks of student 2: 273/3 = 91
• Marks obtained by student 3: 78, 85, 83. Average marks of student 3: 246/3 = 82
• Marks obtained by student 4: 93, 88, 89. Average marks of student 4: 270/3 = 90
• Marks obtained by student 5: 80, 86, 90.5. Average marks of student 5: 256.5/3 = 85.5

Solution:

N, X = list(map(int,input().split()))

marks = []
for _ in range(X):
    sub_marks = list(map(float,input().split()))
    marks.append(sub_marks)
    
for mark in zip(*marks):
    avg = sum(mark)/len(mark)
    print(avg)
    

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