HackerRank SQL Solution - Basic Select - Higher Than 75 Marks

  • Query the Name of any student in STUDENTS who scored higher than 75 Marks. Order your output by the last three characters of each name. If two or more students both have names ending in the same last three characters (i.e.: Bobby, Robby, etc.), secondary sort them by ascending ID.
Input Format:
  • The STUDENTS table is described as follows:
HackerRank SQL Solution - Basic Select - Higher Than 75 Marks
  • The Name column only contains uppercase (A-Z) and lowercase (a-z) letters.
Sample Input:

Sample Output:


/* Editor - MySQL */

select name from students where marks > 75 order by substr(name,-3) , id ;
Note: The problem statement is given by hackerrank.com but the solution is generated by the Geek4Tutorial admin. We highly recommend you solve this on your own, however, you can refer to this in case of help. If there is any concern regarding this post or website, please contact us using the contact form. Thank you!

No comments:

Post a Comment

You might also like

Deploy your Django web app to Azure Web App using App Service - F1 free plan

In this post, we will look at how we can deploy our Django app using the Microsoft Azure app service - a free plan. You need an Azure accoun...