LeetCode Solution - Problem Pow(x, n)

  • Implement pow(x, n), which calculates x raised to the power n (i.e., x^n).
Example 1:

Input: x = 2.00000, n = 10
Output: 1024.00000

LeetCode Solution - Problem Factorial Trailing Zeroes

  • Given an integer n, return the number of trailing zeroes in n!.
  • Note that n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1.
Example 1:

Input: n = 3
Output: 0
Explanation: 3! = 6, no trailing zero.

LeetCode Solution - Problem Palindrome Number

  • Given an integer x, return true if x is a palindrome, and false otherwise. 
Example 1:

Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.

LeetCode Solution - Problem Reverse Integer

  • Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
  • Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:

Input: x = 123
Output: 321

LeetCode Solution - Problem Single Number

  • Given a non-empty array of integers nums, every element appears twice except for one. Find that single one.
  • You must implement a solution with a linear runtime complexity and use only constant extra space.
Example 1:

Input: nums = [2,2,1]
Output: 1

LeetCode Solution - Problem Fizz Buzz

Given an integer n, return a string array answer (1-indexed) where:
  • answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
  • answer[i] == "Fizz" if i is divisible by 3.
  • answer[i] == "Buzz" if i is divisible by 5.
  • answer[i] == i (as a string) if none of the above conditions are true.
Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

HackerRank Python Solution - Regex and Parsing - Validating Roman Numerals

  • You are given a string, and you have to validate whether it's a valid Roman numeral. If it is valid, print True. Otherwise, print False. Try to create a regular expression for a valid Roman numeral.

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